Verifica del 08 febbraio 2002 - solution

1. • Z = 1+2 cosh(x)
   • <µ> = gµ_B 2 sinh(x)/[1+2 cosh(x)]
   • C_B = R 2 x²[2+cosh(x)]/[1+2 cosh(x)]², where R = N_Ak_B. Numerically C_B = 0.59137 J/(mol K) at T=100 K and C_B = 0.0062489 J/(mol K) at T=1000 K
2. • 7.67475×10^-23 J = 479.02 µeV = 3.86356 cm^-1
   • Z -> k_BT/[h²/(2µd²)], for large T
   • C_V = N_Ak_B = R = 8.31447 J/(mol K)
3. • v_F = (2 E_F/m)^½ = 183.50 m/s
   • U/V = 1.10719×10⁶ J/m³
   • P = 738125 Pa = 7.38125 bar
4. • B/z(min) = 55.283 T/m
   • 4 macchie (⁴F_3/2)