Verifica del 03 giugno 2002 - solution
2.19×10
7
and 5.92×10
5
.
Si: 0; P: 3µ
B
(max component) or sqrt(15)µ
B
(abs.value); S: 3µ
B
(max component) or sqrt(27/2)µ
B
(abs.value);
call x=ε/k
B
T; Z=1/(1-exp(-x)); u=ε/(exp(x)-1); C
V
mol
=R x² exp(x)/(exp(x)-1)²; a grande T: R(1-x); a piccola T: R x²exp(-x)
λ=1.78 meV
C
V
mol
= R 3.586×10
-6
(T/K)
3
= 2.982×10
-5
(T/K)
3
created: 29 May 2003
last modified: 3 Nov 2008 by
Nicola Manini