STRUTTURA DELLA MATERIA 1 - 24 Feb. 2015 - solution

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  1. For K, L, M electrons - levels: 85506 eV, 12660 eV, 3180 eV; kinetic energies: 14494 eV, 87340 eV, 96821 eV; speeds: 0.699 108 m/s, 1.560 108 m/s, 1.623 108 m/s
  2. 21.459 J/(mol K)
  3. 2.47 K
  4. Define x=ε/(kB T). (a) CV ≈ (kB/N) x²exp(x)/(1+exp(x)/N)²; (b) CV = N kB x²exp(x)/(1+exp(x))². Good agreement for exp(x) >> N, alias T << ε/(kB log(N)). For x=23.209, (a) CV = 6.191 10-25 J/K; CV = 8.721 10-23 J/K; (b) CV = 6.192 10-25 J/K; CV = 6.192 10-19 J/K
created: 26 Feb 2015 last modified: 26 Feb 2015 by Nicola Manini