STRUTTURA DELLA MATERIA 1 - 15 Apr. 2015 - solution

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  1. 9 components; 0.0289 radians
  2. ε = 0.871 meV; 2.00 meV [> ε!!]; 0.253 meV
  3. Define x=ε/(kB T). (a) CV ≈ (kB/N) x²exp(x)/(1+exp(x)/N)²; (b) CV = N kB x²exp(x)/(1+exp(x))². Good agreement for exp(x) >> N, alias T << ε/(kB log(N)). For x=23.209, (a) CV = 6.191 10-25 J/K; CV = 8.721 10-23 J/K; (b) CV = 6.192 10-25 J/K; CV = 6.192 10-19 J/K
  4. 461.7 nm
created: 9 Jun 2015 last modified: 19 Jun 2015 by Nicola Manini