STRUTTURA DELLA MATERIA 1 - 20 Apr. 2016 - solution

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  1. U = 3Nd(kBT)d+1εD-d0εD/(kBT) xd(exp(x)-1)-1 dx; d+1=3.6; 3NAkB=24.94 J/K
  2. 5.332 µs; 726042 W
  3. 24530 eV; 3604 eV; 3330 eV; 3173 eV; K shell; 42.30
  4. 1.52×10-18 J 1.615×10-10 m
created: 26 Apr 2016
last modified: 26 Apr 2016
by Nicola Manini