STRUTTURA DELLA MATERIA 1 - 11 July 2017 - solutions

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  1. Jmin = (εBA)/ℏ² = 7.20×1048 J-1s-2; EGS = -13.6875 eV
  2. (a) 6.62079×10-106 J m9; (b) 130 (c) 8.31 J/(mol K)
  3. 27.06°
  4. T≥5 eV/kB/x = 4476 K, where x solves (x3 + 3 x² + 6 x +6) exp(-x) = 0.001 π4 /15
created: 12 Jul 2017
last modified: 08 Feb 2019
by Nicola Manini