STRUTTURA DELLA MATERIA 1 - 14 July 2016 - solution

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  1. 3H4: √14; 3H5: √34; 3H6: √58; 3F2: 2; 3F3: 4; 3F4: √32. 3F4
  2. (2 π²/3) kB²T/(ℏωmin) = 5.484×106 kB = 7.571×10-17 J/K
  3. 4.264 eV; 5.293 eV; 1.029 eV
  4. (i) metallo, 0.5 eV; (ii) semiconduttore 0.55 eV; 4.003×10-30=4.394 me
created: 15 July 2016
last modified: 15 July 2016
by Nicola Manini